2x^2+3x=324

Solution for 2x^2+3x=324 equation:

2x^2+3x=324

We move all terms to the left:

2x^2+3x-(324)=0

a = 2; b = 3; c = -324;
Δ = b2-4ac
Δ = 32-4·2·(-324)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-51}{2*2}=\frac{-54}{4}
=-13+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+51}{2*2}=\frac{48}{4}
=12
$